A) \[\frac{5}{19}\]
B) \[\frac{10}{19}\]
C) \[\frac{9}{19}\]
D) None of these
Correct Answer: B
Solution :
The total number of ways in which 2 integers can be chosen from the given 20 integers \[{}^{20}{{C}_{2}}.\] The sum of the selected numbers is odd if exactly one of them is given and one is odd. \[\therefore \]Favourable number of outcomes \[={}^{10}{{C}_{1}}\times {}^{10}{{C}_{1}}\] \[\therefore \]Required probability \[=\frac{{}^{10}{{C}_{1}}\times {}^{10}{{C}_{1}}}{{}^{20}{{C}_{2}}}=\frac{10}{19}.\]
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