A) \[\frac{1}{45}\]
B) \[\frac{1}{90}\]
C) \[\frac{1}{100}\]
D) None of these
Correct Answer: B
Solution :
There are 10 digits \[0,\,\,1,\,\,2,\,\,3,\,\,4,\,\,5,\,\,6,\,\,7,\,\,8,\,\,9.\] The last two digits can be dialled in \[{}^{10}{{P}_{2}}=90\] ways, out of which only one way is favourable, thus the required probability \[=\frac{1}{90}.\]
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