A) \[\frac{5}{13}\]
B) \[\frac{5}{11}\]
C) \[\frac{4}{11}\]
D) \[\frac{3}{11}\]
Correct Answer: B
Solution :
Total number of ways to select 6 persons out of \[11={}^{11}{{C}_{6}}\] Ways to select two ladies \[={}^{4}{{C}_{2}}\] Ways to select four men \[={}^{7}{{C}_{4}}\] \[\therefore \] Probability that committee contain 2 ladies \[=\frac{{}^{4}{{C}_{2}}.{}^{7}{{C}_{4}}}{{}^{11}{{C}_{6}}}=\frac{5}{11}.\]
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