A) \[\frac{6}{71}\]
B) \[\frac{7}{81}\]
C) \[\frac{10}{91}\]
D) None of these
Correct Answer: C
Solution :
Required probability \[=\frac{{}^{3}{{C}_{3}}+{}^{7}{{C}_{3}}+{}^{4}{{C}_{3}}}{{}^{14}{{C}_{3}}}\] \[=\frac{1+35+4}{14\,.\,13\,.\,2}=\frac{40}{14\,.\,26}=\frac{10}{91}.\]
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