A) \[\frac{1}{729}\]
B) \[\frac{1}{24}\]
C) \[\frac{1}{21}\]
D) \[\frac{2}{7}\]
Correct Answer: D
Solution :
Required probability \[=\frac{{}^{2}{{C}_{1}}\times {}^{3}{{C}_{1}}\times {}^{4}{{C}_{1}}}{{}^{9}{{C}_{3}}}=\frac{2\times 3\times 4}{\left( \frac{9\times 8\times 7}{3\times 2} \right)}=\frac{2}{7}\].
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