A) \[\frac{2}{7}\]
B) \[\frac{3}{7}\]
C) \[\frac{4}{7}\]
D) None of these
Correct Answer: A
Solution :
By using digits 1, 2, 3, 4, 5, 6 and 8, total 5 digits numbers = \[^{7}{{P}_{5}}\] And number of ways to form the numbers, they have even digit at both ends \[=4\times 3{{\times }^{5}}{{P}_{3}}\] \[\therefore \] Probability \[=\frac{4\times 3{{\times }^{5}}{{P}_{3}}}{^{7}{{P}_{5}}}=\frac{2}{7}\].
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