JEE Main & Advanced Mathematics Probability Question Bank Use of permutations and combinations in probability

  • question_answer
    Out of 30 consecutive numbers, 2 are chosen at random.  The probability that their sum is odd, is [Kurukshetra CEE 2002]

    A)            \[\frac{14}{29}\]                     

    B)            \[\frac{16}{29}\]

    C)            \[\frac{15}{29}\]                     

    D)            \[\frac{10}{29}\]

    Correct Answer: C

    Solution :

                       The total number of ways in which 2 integers can be chosen from the given 30 integers is \[^{30}{{C}_{2}}.\] The sum of the selected numbers is odd if exactly one of them is even and one is odd.                    \ Favourable number of outcomes = \[^{15}{{C}_{1}}{{.}^{15}}{{C}_{1}}\]                    \[\therefore \] Required probability \[=\frac{^{15}{{C}_{1}}.{{\,}^{15}}{{C}_{1}}}{^{30}{{C}_{2}}}=\frac{15}{29}\].


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