A) \[\frac{15}{91}\]
B) \[\frac{30}{91}\]
C) \[\frac{20}{91}\]
D) \[\frac{24}{91}\]
Correct Answer: D
Solution :
Required probability \[=\frac{4\,.\,5\,.\,6}{{}^{15}{{C}_{3}}}=\frac{24}{91}.\]
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