A) \[\frac{4}{5}\]
B) \[\frac{3}{5}\]
C) \[\frac{2}{5}\]
D) \[\frac{1}{5}\]
Correct Answer: A
Solution :
Total ways \[=10\,\,!\] Two boys can sit side by side in \[2\times 9\,\,!\] ways. So probaibility \[=\frac{2\times 9\,\,!}{10\,\,!}=\frac{1}{5}\] Thus the probability that they are not seated together is \[1-\frac{1}{5}=\frac{4}{5}.\]
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