A) \[\frac{14}{15}\]
B) \[\frac{11}{15}\]
C) \[\frac{7}{15}\]
D) \[\frac{4}{15}\]
Correct Answer: C
Solution :
Required probability = Either the balls are red or the balls are black \[=\frac{^{8}{{C}_{2}}}{^{15}{{C}_{2}}}+\frac{^{7}{{C}_{2}}}{^{15}{{C}_{2}}}=\frac{28+21}{105}\]\[=\frac{49}{105}=\frac{7}{15}\].
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