A) \[\frac{24}{144}\]
B) \[\frac{56}{144}\]
C) \[\frac{68}{144}\]
D) \[\frac{76}{144}\]
Correct Answer: D
Solution :
Required probability \[=\frac{^{5}{{C}_{1}}{{\,}^{4}}{{C}_{1}}}{^{12}{{C}_{1}}^{12}{{C}_{1}}}+\frac{^{7}{{C}_{1}}{{\,}^{8}}{{C}_{1}}}{^{12}{{C}_{1}}{{\,}^{12}}{{C}_{1}}}\]\[=\frac{20+56}{144}=\frac{76}{144}\].
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