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JEE Main & Advanced Physics Semiconducting Devices Question Bank Valve Electronics (Diode and Triode)

  • question_answer
    In a triode amplifier, \[\mu =25,\,{{r}_{p}}=40\] kilo ohm and load resistance \[{{R}_{L}}=10\] kilo ohm. If the input signal voltage is 0.5 volt, then output signal voltage will be [RPMT 1995]

    A)            1.25 volt                                 

    B)            5 volt

    C)            2.5 volt                                   

    D)            10 volt

    Correct Answer: C

    Solution :

                       Voltage gain \[=\frac{{{V}_{\text{out}}}}{{{V}_{\text{in}}}}=\frac{\mu }{1+\frac{{{r}_{p}}}{{{R}_{L}}}}\]\[\Rightarrow \frac{{{V}_{\text{out}}}}{0.5}=\frac{25}{1+\frac{40\times {{10}^{3}}}{10\times {{10}^{3}}}}\]                    \[\Rightarrow {{V}_{\text{out}}}=2.5V\].


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