A) 30.42
B) 29.57
C) 28.18
D) 27.15
Correct Answer: B
Solution :
Voltage gain \[{{A}_{v}}=\frac{\mu }{1+\frac{{{r}_{p}}}{{{R}_{L}}}}\] and \[\mu ={{r}_{p}}\times {{g}_{m}}\] Þ\[{{r}_{p}}=\frac{42}{2\times {{10}^{-3}}}=21000\,\Omega \]Þ\[{{A}_{v}}=\frac{42}{1+\frac{21000}{50\times {{10}^{3}}}}=29.57\]You need to login to perform this action.
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