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JEE Main & Advanced Physics Semiconducting Devices Question Bank Valve Electronics (Diode and Triode)

  • question_answer
    For a triode, at \[{{V}_{g}}=-1\] volt, the following observations were taken \[{{V}_{p}}=75V,\,{{I}_{p}}=2mA\], \[{{V}_{p}}=100V,\,{{I}_{p}}=4mA\]. The value of plate resistance will be              [MP PMT 1989]

    A)            25 kW                                      

    B)            20.8 kW

    C)            12.5 kW                                  

    D)            100 kW

    Correct Answer: C

    Solution :

               \[{{r}_{p}}=\frac{{{V}_{{{p}_{1}}}}-{{V}_{{{p}_{2}}}}}{{{I}_{{{p}_{1}}}}-{{I}_{{{P}_{2}}}}}=\frac{75-100}{(2-4)\times {{10}^{-3}}}\]=12.5 ´ 103W =12.5kW.


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