A) 25 kW
B) 75 kW
C) 7.5 kW
D) 2.5 kW
Correct Answer: A
Solution :
Voltage amplification \[{{A}_{v}}=\frac{\mu }{1+\frac{{{r}_{p}}}{{{R}_{L}}}}\] \[\Rightarrow \,\,\,\,\,25=\frac{\mu }{1+\frac{{{r}_{p}}}{50\times {{10}^{3}}}}\] ......(i) and \[30=\frac{\mu }{1+\frac{{{r}_{p}}}{100\times {{10}^{3}}}}\] ......(ii) an solving equation (i) and (ii), \[{{r}_{p}}=25k\Omega .\]
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