JEE Main & Advanced Physics Semiconducting Devices Question Bank Valve Electronics (Diode and Triode)

  • question_answer
    When plate voltage in diode valve is increased from 100 volt to 150 volt then plate current increases from 7.5 mA to 12 mA. The dynamic plastic resistance will be                  [RPMT 2000]

    A)            10 kW                                      

    B)            11 kW

    C)            15 kW                                      

    D)            11.1 kW

    Correct Answer: D

    Solution :

               \[{{r}_{p}}=\frac{\Delta {{V}_{p}}}{\Delta {{i}_{p}}}=\frac{150-100}{(12-7.5)\times {{10}^{-3}}}=\frac{50}{4.5}\times {{10}^{3}}=11.1k\Omega \].


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