A) 5 kW
B) 25 kW
C) 20 kW
D) 50 kW
Correct Answer: A
Solution :
Voltage amplification \[{{A}_{v}}=\frac{\mu }{1+\frac{{{r}_{p}}}{{{R}_{L}}}}=\frac{{{r}_{p}}\times {{g}_{m}}\times {{R}_{L}}}{{{R}_{L}}+{{r}_{p}}}\] \[\Rightarrow 10=\frac{20\times {{10}^{3}}\times 2.5\times {{10}^{-3}}\times {{R}_{L}}}{({{R}_{L}}+20\times {{10}^{3}})}\]\[\Rightarrow {{R}_{L}}=5k\Omega \].
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