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JEE Main & Advanced Physics Semiconducting Devices Question Bank Valve Electronics (Diode and Triode)

  • question_answer
    In a triode, \[{{g}_{m}}=2\times {{10}^{-3}}oh{{m}^{-1}};\,\mu =42\], resistance load, \[R=50\] kilo ohm. The voltage amplification obtained from this triode will be                                                    [MNR 1999]

    A)            30.42                                       

    B)            29.57

    C)            28.18                                       

    D)            27.15

    Correct Answer: B

    Solution :

                       Voltage gain \[{{A}_{v}}=\frac{\mu }{1+\frac{{{r}_{p}}}{{{R}_{L}}}}\] and \[\mu ={{r}_{p}}\times {{g}_{m}}\] Þ\[{{r}_{p}}=\frac{42}{2\times {{10}^{-3}}}=21000\,\Omega \]Þ\[{{A}_{v}}=\frac{42}{1+\frac{21000}{50\times {{10}^{3}}}}=29.57\]


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