A) \[{{e}^{5}}\]
B) \[{{e}^{6}}+1\]
C) \[\frac{{{e}^{6}}+9}{2}\]
D) \[{{\log }_{e}}6\]
Correct Answer: C
Solution :
\[\int_{{}}^{{}}{\frac{dy}{{{e}^{-2y}}}}=\int_{{}}^{{}}{dx}\] Þ \[\frac{{{e}^{2y}}}{2}=x+c\] At \[x=5,\ y=0\]Þ \[c=-\frac{9}{2}\]; \[\therefore \]For \[y=3,\ x=\frac{{{e}^{6}}+9}{2}\].You need to login to perform this action.
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