A) \[y=c{{e}^{{{x}^{2}}}}\]
B) \[{{y}^{2}}=2{{x}^{2}}+c\]
C) \[y={{e}^{-{{x}^{2}}}}+c\]
D) \[y={{x}^{2}}+c\]
Correct Answer: A
Solution :
\[\int_{{}}^{{}}{\frac{dy}{y}=\int_{{}}^{{}}{2xdx}}\]Þ\[{{\log }_{e}}y={{x}^{2}}+c\] Þ \[y={{e}^{{{x}^{2}}+c}}={{e}^{c}}{{e}^{{{x}^{2}}}}\]Þ\[y=c{{e}^{{{x}^{2}}}}\].You need to login to perform this action.
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