A) \[y+{{e}^{({{e}^{x}}+x+c)}}=0\]
B) \[\log y={{e}^{x}}+x+c\]
C) \[\log y+{{e}^{x}}=x+c\]
D) None of these
Correct Answer: B
Solution :
\[\frac{dy}{dx}=y({{e}^{x}}+1)\] Þ \[\frac{dy}{y}=({{e}^{x}}+1)dx\] Integrating both sides, we get \[\log y={{e}^{x}}+x+c\].You need to login to perform this action.
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