A) \[x\sec y\tan y=c\]
B) \[cx=\sec y+\tan y\]
C) \[cy=\sec x\tan x\]
D) \[cy=\sec x+\tan x\]
Correct Answer: B
Solution :
\[x\sec y\frac{dy}{dx}=1\] Þ \[\sec ydy=\frac{dx}{x}\] On integrating both sides, we get \[\log (\sec y+\tan y)=\log x+\log c\]Þ \[\sec y+\tan y=cx\].You need to login to perform this action.
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