A) \[y=\frac{{{x}^{3}}}{3}+\frac{\cos 3x}{3}+c\]
B) \[y=\frac{{{x}^{3}}}{3}-\frac{\cos 3x}{3}+c\]
C) \[y=\frac{{{x}^{3}}}{3}+\sin 3x+c\]
D) None of these
Correct Answer: B
Solution :
\[\frac{dy}{dx}={{x}^{2}}+\sin 3x\]. On integrating, \[y=\frac{{{x}^{3}}}{3}-\frac{\cos 3x}{3}+c\].You need to login to perform this action.
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