A) \[y+2\cos y=c\]
B) \[y-2\sin y=c\]
C) \[x=\cot y+c\]
D) \[y=\cot x+c\]
Correct Answer: C
Solution :
\[\frac{dy}{dx}+{{\sin }^{2}}y=0\] Þ \[-\frac{dy}{{{\sin }^{2}}y}=dx\]. On integrating, we get \[x=\cot y+c\].You need to login to perform this action.
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