A) \[y={{e}^{x}}(\sin x-\cos x)+c\]
B) \[y={{e}^{x}}(\cos x-\sin x)+c\]
C) \[y={{e}^{x}}\sin x+c\]
D) \[y={{e}^{x}}\cos x+c\]
Correct Answer: C
Solution :
Given equation \[\frac{dy}{dx}={{e}^{x}}(\sin x+\cos x)\] Þ \[dy={{e}^{x}}(\sin x+\cos x)dx\] On integrating, we get \[y={{e}^{x}}\sin x+c\].You need to login to perform this action.
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