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JEE Main & Advanced Mathematics Differential Equations Question Bank Variable Separable type differential equations

  • question_answer
    Solution of differential equation \[\frac{dy}{dx}=\sin x+2x\], is [MP PET 1997]

    A)                 \[y={{x}^{2}}-\cos x+c\] 

    B)                 \[y=\cos x+{{x}^{2}}+c\]

    C)                 \[y=\cos x+2\]      

    D)                 \[y=\cos x+2+c\]

    Correct Answer: A

    Solution :

                    \[\int_{{}}^{{}}{dy}=\int_{{}}^{{}}{\sin xdx}+\int_{{}}^{{}}{2xdx}\]Þ\[y=-\cos x+{{x}^{2}}+c\].


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