A) \[-\exp (x)\]
B) \[-\exp (-x)\]
C) ? 1
D) \[\exp (x)-2\]
Correct Answer: C
Solution :
\[\frac{dy}{dx}-y=1\] Þ \[\frac{dy}{1+y}=dx\] Integrating both sides \[\log (1+y)=x+c\]Þ \[1+y={{e}^{x}}.{{e}^{c}}\] \[\because x=0,\,\,y=-1\].Then, \[1-1=e.{{e}^{c}}\]Þ\[{{e}^{c}}=0\] Therefore solution \[1+y={{e}^{x}}\times 0\Rightarrow y(x)=-1\].
You need to login to perform this action.
You will be redirected in
3 sec
