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JEE Main & Advanced Mathematics Differential Equations Question Bank Variable Separable type differential equations

  • question_answer
    The solution of the equation \[(2y-1)\,\,dx-(2x+3)\,dy=0\] is [Kerala (Engg.)  2002]

    A)                 \[\frac{2x-1}{2y+3}=c\]    

    B)                 \[\frac{2y+1}{2x-3}=c\]

    C)                 \[\frac{2x+3}{2y-1}=c\]    

    D) s                 \[\frac{2x-1}{2y-1}=c\]

    Correct Answer: C

    Solution :

                       \[\frac{dy}{2y-1}=\frac{dx}{2x+3}\]                 Þ \[\frac{1}{2}\log (2y-1)=\frac{1}{2}\log (2x+3)+\log c\] Þ \[\frac{2x+3}{2y-1}=c\].


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