A) \[\frac{4i+3j-k}{\sqrt{26}}\]
B) \[\frac{2i-6j-3k}{7}\]
C) \[\frac{3i-2j+6k}{7}\]
D) \[\frac{2i-3j-6k}{7}\]
Correct Answer: C
Solution :
Perpendicular vector to a and b\[=a\times b\] and perpendicular unit vector \[=\frac{a\times b}{|a\times b|}\]. \[a\times b=\left| \,\begin{matrix} i & \,\,j & \,\,\,k \\ 2 & -6 & -3 \\ 4 & \,\,3 & -1 \\ \end{matrix}\, \right|\]\[=15i-10j+30k\] and \[|a\times b|\,=\sqrt{225+100+900}=35\] \ Required vector\[=\frac{15i-10j+30k}{35}=\frac{3i-2j+6k}{7}\].
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