A) 0
B) 1
C) 2
D) 3
Correct Answer: A
Solution :
\[\mathbf{a}\,.\,\mathbf{c}=1\] and \[\mathbf{b}\,.\,\mathbf{c}=1\] Given that\[(\mathbf{a}\times \mathbf{b})\times \mathbf{c}=(\mathbf{c}\,.\,\mathbf{a})\mathbf{b}-(\mathbf{c}\,.\,\mathbf{b})\,\mathbf{a}=\mu \,\mathbf{b}+\lambda \mathbf{a}\] where \[\mu =\mathbf{c}\,.\,\mathbf{a}=1,\,\,\lambda =-\,(\mathbf{c}\,.\,\mathbf{b})=-\,1\] \[\Rightarrow \,\,\mu +\lambda =1-1=0\].You need to login to perform this action.
You will be redirected in
3 sec