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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Velocity of Simple Harmonic Motion

  • question_answer
    If the displacement of a particle executing SHM is given by \[y=0.30\sin (220t+0.64)\] in metre, then the frequency and maximum velocity of the particle is              [AFMC 1998]

    A)            35 Hz, 66 m / s                     

    B)            45 Hz, 66 m / s

    C)            58 Hz, 113 m / s                   

    D)            35 Hz, 132 m / s

    Correct Answer: A

    Solution :

                       \[n=\frac{\omega }{2\pi }=\frac{220}{2\pi }=35\,Hz\]            \[{{v}_{\max }}=\omega \,a=220\times 0.30\,m/s=66\,m/s\]


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