A) 3 rad/sec
B) 0.5 rad/sec
C) 1 rad/sec
D) 2 rad/sec
Correct Answer: D
Solution :
\[{{v}_{\max }}=a\omega \] and \[{{A}_{\max }}=a{{\omega }^{2}}\]Þ \[\omega =\frac{{{A}_{\max }}}{{{v}_{\max }}}=\frac{4}{2}=2\,rad/sec\]
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