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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Velocity of Simple Harmonic Motion

  • question_answer
    The angular velocities of three bodies in simple harmonic motion are \[{{\omega }_{1}},\,{{\omega }_{2}},\,{{\omega }_{3}}\] with their respective amplitudes as \[{{A}_{1}},\,{{A}_{2}},\,{{A}_{3}}\]. If all the three bodies have same mass and velocity, then                                                           [BHU 2002]

    A)            \[{{A}_{1}}{{\omega }_{1}}={{A}_{2}}{{\omega }_{2}}={{A}_{3}}{{\omega }_{3}}\] 

    B)            \[{{A}_{1}}{{\omega }_{1}}^{2}={{A}_{2}}{{\omega }_{2}}^{2}={{A}_{3}}{{\omega }_{3}}^{2}\]

    C)            \[{{A}_{1}}^{2}{{\omega }_{1}}={{A}_{2}}^{2}{{\omega }_{2}}={{A}_{3}}^{2}{{\omega }_{3}}\]        

    D)            \[{{A}_{1}}^{2}{{\omega }_{1}}^{2}={{A}_{2}}^{2}{{\omega }_{2}}^{2}={{A}^{2}}\]

    Correct Answer: A

    Solution :

                       Velocity is same. So by using \[v=a\omega \]            Þ \[{{A}_{1}}{{\omega }_{1}}={{A}_{2}}{{\omega }_{2}}={{A}_{3}}{{\omega }_{3}}\]


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