A) 0.01
B) 0.05
C) 0.5
D) 0.25
Correct Answer: C
Solution :
Acceleration \[A={{\omega }^{2}}y\]\[\Rightarrow \omega =\sqrt{\frac{A}{y}}=\sqrt{\frac{0.5}{0.02}}=5\] Maximum velocity \[{{v}_{\max }}=a\omega =0.1\times 5=0.5\]You need to login to perform this action.
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