A) 0.10 m / s
B) 0.15 m / s
C) 0.8 m / s
D) 0.26 m / s
Correct Answer: B
Solution :
\[{{v}_{\max }}=a\omega =a\times \frac{2\pi }{T}=(50\times {{10}^{-3}})\times \frac{2\pi }{2}=0.15\,m/s\]You need to login to perform this action.
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