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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Velocity of Simple Harmonic Motion

  • question_answer
    The instantaneous displacement of a simple pendulum oscillator is given by \[x=A\cos \left( \omega t+\frac{\pi }{4} \right)\]. Its speed will be maximum at time                                                        [CPMT 2000]

    A)            \[\frac{\pi }{4\omega }\]

    B)            \[\frac{\pi }{2\omega }\]

    C)            \[\frac{\pi }{\omega }\]         

    D)            \[\frac{2\pi }{\omega }\]

    Correct Answer: A

    Solution :

                       \[x=A\cos \left( \omega t+\frac{\pi }{4} \right)\] and \[v=\frac{dx}{dt}=-A\omega \sin \left( \omega \,t+\frac{\pi }{4} \right)\]            For maximum speed,


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