A) \[{{l}_{1}}\] is changed to \[{{G}^{2}}{{I}_{1}}\]
B) \[{{I}_{2}}\] is changed to \[{{G}^{2}}{{I}_{2}}\]
C) \[{{I}_{1}}\] is changed to \[{{\text{I}}_{\text{1}}}\text{/}{{\text{G}}^{\text{2}}}\]
D) \[{{I}_{2}}\] is changed to \[{{\text{I}}_{2}}\text{/}{{\text{G}}^{\text{2}}}\]
Correct Answer: B
Solution :
\[\frac{{{n}_{2}}}{{{n}_{1}}}=G\] \[I_{2}^{'}={{G}^{2}}{{I}_{2}}\]You need to login to perform this action.
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