A) 10
B) 50
C) 100
D) 200
Correct Answer: D
Solution :
Unbalanced force, \[F=me{{\omega }^{2}}\] \[\omega =\frac{2\pi N}{60}\] \[\therefore \,\,\,\,\,\,\,F\propto m{{N}^{2}}\] \[\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{m}_{1}}N_{1}^{2}}{{{m}_{1}}N_{2}^{2}}=\frac{m}{\left( \frac{m}{2} \right)}\times \left( \frac{3000}{300} \right)=2\times 100=200\]You need to login to perform this action.
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