A) 3650 K
B) 4500 K
C) 5800 K
D) 6150 K
Correct Answer: C
Solution :
Temperature of the Sun, \[{{T}_{s}}={{\left[ \frac{{{L}^{2}}{{G}_{s}}}{{{r}^{2}}\sigma } \right]}^{1/4}}\] Where L = mean distance between the sun and the Earth \[=1.5\times {{10}^{11}}m\] r = radius of the Sun \[=7\times {{10}^{8}}m\] \[{{G}_{s}}=\] rate of radiation from the sun \[=1400\,\text{W/}{{\text{m}}^{\text{2}}}\] \[\sigma \,\,=\] Stefan-Boltzmann constan \[=5.675\times {{10}^{-\,8}}\,\text{W/(}{{\text{m}}^{\text{2}}}\text{.K)}\] \[{{T}_{s}}={{\left[ \frac{{{(1.5\times {{10}^{11}})}^{2}}\times 1400}{{{(7\times {{10}^{8}})}^{2}}\times 5.675\times {{10}^{-\,8}}} \right]}^{1/4}}\] = 5800 K \[=900w/{{m}_{2}}\]
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