A) 1%
B) 2%
C) 3%
D) 4%
Correct Answer: B
Solution :
To produce 5 beats/sec. Frequency of one wire should be increase up to 505 \[Hz\]. i.e. increment of 1% in basic frequency. \[n\propto \sqrt{T}\] or \[T\propto {{n}^{2}}\]Þ \[\frac{\Delta T}{T}=2\frac{\Delta n}{n}\] Þ percentage change in Tension =\[2\,(1%)=2%\]You need to login to perform this action.
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