A) \[\lambda =\frac{{{n}^{2}}}{2l}\]
B) \[\lambda =\frac{{{l}^{2}}}{2n}\]
C) \[\lambda =\frac{2l}{n}\]
D) \[\lambda =2l\ n\]
Correct Answer: C
Solution :
\[\lambda =\frac{2l}{p}\] (p = Number of loops)You need to login to perform this action.
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