A) 2
B) 4
C) 8
D) 1
Correct Answer: D
Solution :
Fundamental frequency \[n=\frac{1}{2l}\sqrt{\frac{T}{\pi {{r}^{2}}\rho }}\] where m = Mass per unit length of wire Þ\[n\propto =\frac{1}{lr}\Rightarrow \frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\times \frac{{{l}_{2}}}{{{l}_{1}}}=\frac{r}{2r}\times \frac{2L}{L}=\frac{1}{1}\]You need to login to perform this action.
You will be redirected in
3 sec