A) 1 m
B) \[\frac{1}{2}m\]
C) 5 m
D) 2pm
Correct Answer: B
Solution :
Given equation of stationary wave is \[y=\sin 2\pi x\cos 2\pi t\], comparing it with standard equation \[y=2A\sin \frac{2\pi x}{\lambda }\cos \frac{2\pi x}{\lambda }\] We have \[\frac{2\pi x}{\lambda }=2\pi x\] Þ \[\lambda =1m\] Minimum distance of string (first mode)\[{{L}_{\min }}\,=\frac{\lambda }{2}=\frac{1}{2}m\]You need to login to perform this action.
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