A) 16 ml
B) 32 ml
C) 35 ml
D) 70 ml
Correct Answer: A
Solution :
In the neutralization of acid and base N × V of both must be equivalent N × V of HCl = 0.1 × 100 = 10 N × V of NaOH = 0.2 × 30 = 6 as to obtain 10 N × V of base 4 N × V of base is required N × V of KOH = 0.25 × 16 = 4 N1V1 = \[\underset{NaOH}{\mathop{N\times V\ }}\,+\ \underset{KOH}{\mathop{N\times V}}\,\] 0.1 × 100 = 0.2 × 30 + 0.25 × V 10 = 6 + 0.25 V \[V=\frac{400}{0.25}\] Þ V = 16 mlYou need to login to perform this action.
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