A) 0.5 N
B) 0.9 N
C) 0.3 N
D) 0.6 N
Correct Answer: A
Solution :
\[{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}~=~{{N}_{3}}{{V}_{3}}\] \[200\times 0.6+100\times 0.3={{N}_{3}}{{V}_{3}}\,\text{and}{{V}_{3}}={{V}_{2}}+\,{{V}_{1}}\]\[=\ 300\ ml\] \[\therefore \ {{N}_{3}}\ =\ 0.5\ N\]You need to login to perform this action.
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