A) 10ml of \[{{H}_{2}}\]
B) 5ml of \[{{H}_{2}}\]
C) 10ml of \[{{O}_{2}}\]
D) 5ml of \[{{O}_{2}}\]
Correct Answer: D
Solution :
\[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\to {{H}_{2}}O\] 1 mole \[\frac{1}{2}\]mole 1 mole 1 volume \[\frac{1}{2}\]volume 1ml \[{{H}_{2}}\] reacts with \[\frac{1}{2}\]ml \[{{O}_{2}}\] 30ml of \[{{H}_{2}}\] reacts with \[=\frac{1}{2}\times 30=15ml\] \[{{O}_{2}}\] (20-15) = 5ml of\[{{O}_{2}}\] will left at the end of the reaction.
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