A) \[NH_{4}^{+}\]
B) \[BF_{4}^{-}\]
C) \[Xe{{F}_{4}}\]
D) \[SC{{l}_{4}}\]
Correct Answer: C
Solution :
Xe ground state Xe double excitation \[Xe{{F}_{4}}\] \[s{{p}^{3}}{{d}^{2}}\]- hybridizationYou need to login to perform this action.
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