A) Decreases
B) Increases
C) Does not change
D) Becomes zero
Correct Answer: A
Solution :
As the s-character of hybridized orbitals decreases the bond angle also decreases In \[s{{p}^{3}}\]hybridisation: s-character 1/4, bond angle \[{{109}^{o}}\] In \[s{{p}^{2}}\]hybridisation: s-character 1/3, bond angle \[{{120}^{o}}\] In sp hybridisation: s-character 1/2, bond angle \[{{180}^{o}}\]
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