A) 10 : 8
B) 9 : 1
C) 4 : 1
D) 2 : 1
Correct Answer: C
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}+1}{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}-1} \right)}^{2}}=\left( \frac{\sqrt{\frac{9}{1}}+1}{\sqrt{\frac{9}{1}}-1} \right)=\frac{4}{1}\]
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