A) Leads the second by p
B) Lags the second by p
C) Leads the second by \[\frac{\pi }{2}\]
D) Lags the second by \[\frac{\pi }{2}\]
Correct Answer: D
Solution :
\[{{y}_{1}}=a\sin \omega \,t,\ {{y}_{2}}=a\cos \omega \,t=a\sin \left( \omega \,t+\frac{\pi }{2} \right)\]You need to login to perform this action.
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